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50(10x^2-350x+120)=0
We multiply parentheses
500x^2-17500x+6000=0
a = 500; b = -17500; c = +6000;
Δ = b2-4ac
Δ = -175002-4·500·6000
Δ = 294250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{294250000}=\sqrt{250000*1177}=\sqrt{250000}*\sqrt{1177}=500\sqrt{1177}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17500)-500\sqrt{1177}}{2*500}=\frac{17500-500\sqrt{1177}}{1000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17500)+500\sqrt{1177}}{2*500}=\frac{17500+500\sqrt{1177}}{1000} $
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